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30h^2-11h-30=0
a = 30; b = -11; c = -30;
Δ = b2-4ac
Δ = -112-4·30·(-30)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3721}=61$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-61}{2*30}=\frac{-50}{60} =-5/6 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+61}{2*30}=\frac{72}{60} =1+1/5 $
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